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Pumps and energy

Hydraulic, shaft and electrical power of a pump

Quick answer

Three power numbers explain every pump energy calculation: the power in the liquid, the power on the shaft and the power drawn from the supply. Efficiency links them.

By Tanmay Sharma, founder of Rotec AI · Last reviewed 6 November 2026

The power chain

Electrical power goes into the motor. The motor turns the shaft, and the shaft drives the impeller. The impeller gives energy to the liquid. Each step loses some energy, so each number is a little larger than the one after it.

PowerWhat it isHow to get it
Hydraulic power (kW)The useful power in the liquid leaving the pumpFlow in m3/s x total head in m x density in kg/m3 x 9.81, divided by 1000
Shaft power (kW)The power the motor delivers to the pump shaftHydraulic power divided by pump efficiency
Electrical input power (kW)The power drawn from the supplyShaft power divided by motor efficiency

A worked example with water

A pump delivers 68 m3/h against a total head of 47 m, with a pump efficiency of 60% and a motor efficiency of 90%.

StepCalculationResult
Flow in m3/s68 divided by 36000.0189 m3/s
Hydraulic power0.0189 x 47 x 1000 x 9.81 divided by 10008.7 kW
Shaft power8.7 divided by 0.6014.5 kW
Electrical input14.5 divided by 0.9016.1 kW

Where the energy goes

Checking a pump in the field

Takeaway. Hydraulic power is the useful part. Everything above it is the cost of losses, so increase the efficiency or reduce the head and flow you do not need.
Put it to work in the tool

Related reading

Why pump energy matters, and where to startPump curve, system curve and operating pointAffinity lawsFive ways to cut pump energy, and when each one fitsWorked exampleCavitation and NPSH
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