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Cement plant

Counter shaft and pinion bearings: how to work out the loads

A step-by-step method for the radial and axial load on a mill pinion counter shaft, and what to check before trusting the result.

The shaft

A counter shaft sits between a coupling and a pinion that meshes with a girth gear. Two bearings carry it, usually one located and one free.

The method

StepFormulaNote
TorqueT = 9,550 × P ÷ n (N·m)P in kW, n in rpm
Tangential forceFt = 2 × T ÷ dd = pinion pitch diameter, in metres
Radial forceFr = Ft × tan α ÷ cos βα = pressure angle (20° common). β = helix angle, 0 for a spur gear
Axial forceFa = Ft × tan βZero for a spur gear
ReactionsMoments about each bearingWeights act down, gear forces act in the plane of the mesh
Service factorMultiply the gear forceState it. A factor of two is not a default

Worked sizes

For 2,500 kW at 124 rpm the torque is about 192.5 kN·m. On an 810 mm pinion the tangential force is about 475 kN, and at 20° the radial force is about 173 kN. The coupling and the weight of the shaft and pinion are small next to that.

Check before you trust the result

Lubrication and monitoring (typical practice)

Takeaway. The method is short. The risk is in the inputs, so make every sheet use the same ones.
Put it to work in the tool

Related reading

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